C Problem; Expected expression

Hello,
I just started with C recently, and I'm encountering my first problems.
I created a small script for a game, here it is:

 #include <stdio.h> #include <stdlib.h> #include <string.h> int type, isFixe, val, val1, val2; char *typeHex; void jet(int type, int isFixe, int val1, int val2) { switch(type) { case 1: typeHex[2] = {'7','D'}; break; case 2: typeHex[2] = {'7','C'}; break; case 3: typeHex[2] = {'7','6'}; break; case 4: typeHex[2] = {'7','E'}; break; case 5: typeHex[2] = {'7','7'}; break; case 6: typeHex[2] = {'7','B'}; break; } if(isFixe == 1) { printf("Here is the roll to copy: %s#0#0#0#0d0+%d",typeHex,val1); } else { printf("Here is the roll to copy: %s#0#0#0#1d0+%d",typeHex,val2-1,val1-1); } } int main(int argc, char *argv[]) { printf("\tJet Creation Software by Psycko\n\n"); printf("==============================================\n\n"); printf("1. Vitality\t2. Wisdom\n3. Strength\t4. Intelligence\n5. Agility\t6. Luck\n\n"); printf("Enter the roll type number: "); scanf("%d",&type); printf("Fixed roll(1) or non-fixed roll(0)?"); scanf("%d",&isFixe); if(isFixe == 1) { printf("Value: "); scanf("%d",&val); jet(type,1,val,0); } else { printf("Value 1: "); scanf("%d",&val1); printf("Value 2: "); scanf("%d",&val2); jet(type,0,val1,val2); } printf("\n\n"); system("pause"); } 

Only the part in bold is concerned.
However, during compilation, the well-known Windows console returns:

test.c: In function 'jet':
test.c:12:23: error: expected expression before '{' token
test.c:13:23: error: expected expression before '{' token
test.c:14:23: error: expected expression before '{' token
test.c:15:23: error: expected expression before '{' token
test.c:16:23: error: expected expression before '{' token
test.c:17:23: error: expected expression before '{' token

So I'm turning to you now in hopes of finding a solution.

Good night! :p