Mb to MB conversion and difference.

And here's a little summary of this exciting debate:
(source: Wikipedia)

The standardization of binary prefixes in 1998 by the International Electrotechnical Commission specifies the following prefixes to represent powers of 2:

kibi for "kilo binary";
mebi for "mega binary";
gibi for "giga binary";
tebi for "tera binary";
and so on.

Regarding multiples of the byte, this gives[2]:

1 kibibyte (Kio) = 2^10 bytes = 1,024 bytes
1 mebibyte (Mio) = 2^20 bytes = 1,024 Kio = 1,048,576 bytes
1 gibibyte (Gio) = 2^30 bytes = 1,024 Mio = 1,073,741,824 bytes
1 tebibyte (Tio) = 2^40 bytes = 1,024 Gio = 1,099,511,627,776 bytes
1 pebibyte (Pio) = 2^50 bytes = 1,024 Tio = 1,125,899,906,842,624 bytes
1 exbibyte (Eio) = 2^60 bytes = 1,024 Pio = 1,152,921,504,606,846,976 bytes
1 zebibyte (Zio) = 2^70 bytes = 1,024 Eio = 1,180,591,620,717,411,303,424 bytes
1 yobibyte (Yio) = 2^80 bytes = 1,024 Zio = 1,208,925,819,614,629,174,706,176 bytes

The prefixes kilo, mega, giga, tera, etc. correspond to the same multipliers as in all other fields: powers of 10. Applied to computing, this gives:

1 kilobyte (ko) = 10^3 bytes = 1,000 bytes
1 megabyte (Mo) = 10^6 bytes = 1,000 ko = 1,000,000 bytes
1 gigabyte (Go) = 10^9 bytes = 1,000 Mo = 1,000,000,000 bytes
1 terabyte (To) = 10^12 bytes = 1,000 Go = 1,000,000,000,000 bytes
1 petabyte (Po) = 10^15 bytes = 1,000 To = 1,000,000,000,000,000 bytes

Traditional multiples [edit]
Incorrectly according to the SI, and before the 1998 standardization, derived units such as kilobyte, megabyte, gigabyte were used to represent the following values in powers of 2:

1 kilobyte (Ko) = 2^10 bytes = 1,024 bytes, or 2 to the power of 10
1 megabyte (Mo) = 2^20 bytes = 1,024 Ko = 1,048,576 bytes
1 gigabyte (Go) = 2^30 bytes = 1,024 Mo = 1,073,741,824 bytes
1 terabyte (To) = 2^40 bytes = 1,024 Go = 1,099,511,627,776 bytes
1 petabyte (Po) = 2^50 bytes = 1,024 To = 1,125,899,906,842,624 bytes
1 exabyte (Eo) = 2^60 bytes = 1,024 Po = 1,152,921,504,606,846,976 bytes
1 zettabyte (Zo) = 2^70 bytes = 1,024 Eo = 1,180,591,620,717,411,303,424 bytes
1 yottabyte (Yo) = 2^80 bytes = 1,024 Zo = 1,208,925,819,614,629,174,706,176 bytes

So since 1998: 1 kibibyte = 1024 bytes
1 kilobyte = 1000 bytes

If we read the Wikipedia page: "In the usage popularized by computer scientists..."
Unfortunately, it is not "computer scientists" who define the kilogram.

The kilogram is defined by the BIPM, and it is equal to 10 to the power of 3. Nothing else.

Just as they are not going to redefine the number of seconds in a minute to align with the frequencies of the quartz present in computers.

And it is also clearly stated:
"At the time of '32K' RAM computers, this confusion was not very dangerous, since the difference between 2^10 and 10^3 is only 2.4%. Nowadays, however, with the dizzying growth of memory and storage device capacities, these differences lead to increasingly larger errors."

So no, this confirms that it is a mistake, perpetuated year after year by software publishers and teachers.

indeed,
and as a reminder:
1 Kibi == 1024
1 Mebi == 1024 Ki
1 Gibi == 1024 Mi
1 Tebi == 1024 Gi
etc ... etc....
https://fr.wikipedia.org/wiki/Kibi
--

and ... Here we go!

once again,
the speed of a connection is not expressed in MO or Mb or MB but in bit/s.
MO or MB are megabytes (a storage capacity).
4 Mbit/s is 4 Mbit/s
in theory, you could convert it by dividing by 8 to get MO/S (megabytes per second) but it's much less significant
that would be 0.5 MO/S, not great.
see also:
the difference between go and gb of bandwidth#9
--

and ... Voili Voilou Voila !

There are still some who confuse byte and bit!

a byte = one octet
one octet = 8 bits

therefore, one should not read a MegaByte but a megaBIT.

actually,
we are lazy and saying gB instead of gibiB is acceptable for giving an order of magnitude (and that's often the case) but it is no longer acceptable when it comes to expressing an absolute value.
here’s an example:

bruno@leon:~$ df Filesystem 1K-blocks Used Available Use% Mounted on /dev/hda2 18287088 2480400 14877732 15% / udev 10240 80 10160 1% /dev devshm 256232 0 256232 0% /dev/shm /dev/md0 980416536 675481988 304934548 69% /home bruno@leon:~$ df -h Filesystem Size Used Avail Use% Mounted on /dev/hda2 18G 2.4G 15G 15% / udev 10M 80K 10M 1% /dev devshm 251M 0 251M 0% /dev/shm /dev/md0 935G 645G 291G 69% /home bruno@leon:~$ df --si Filesystem Size Used Avail Use% Mounted on /dev/hda2 19G 2.6G 16G 15% / udev 11M 82k 11M 1% /dev devshm 263M 0 263M 0% /dev/shm /dev/md0 1.1T 692G 313G 69% /home bruno@leon:~$ 

--

and ... Voili Voilou Voila !

Bonjour,
128 Mo équivaut à 128 000 Ko.

Thank you very much

Bonjour, vous allez encore vous énerver quand vous allez voir ma question mais sur dailymotion, je ne peux pas ajouter une vidéo car elle est trop grande mais j'ai l'impression que ce n'est pas ce problème-là
alors, 198,948 KO est = à combien de MO ?
Merci d'avance

MB = Mo ou pas

How many MB can you put on a 800 MB CD?

Thank you.

Hey no, precisely. For a while now we've been explaining that we're counting in 1024 and not in 1000. So my calculation is correct.

234 ko ça fait 0,234 MB.

Thank you in advance...

8 mb (megabit) = 1 mo (megabyte)
but beware 8 mB (megabyte) = 8 mo (megabyte)

So actually, if I understood correctly

1Mo = 1MB = 8Mb = 1024 Kio (or KiB)

and that in ads they give us a value in Go or GB, in reality they are giving us a value in Gio or GiB, which when read by our computer gives us a value in Go or GB, resulting in a smaller outcome, creating an impression of loss, while in fact, it's just a simple lie on paper :)

P.S.: I realize I may have made some mistakes in my summary since I read all the posts in one go, so I apologize if that's the case :s

303,6 Mo équivaut à 303,6 Mb.

Hello,

I support Thrax's statements!

Kudos to the moderators for your patience and your
respect towards the CCM members.

It's all to your credit :-)

Lipun.

ATM is a level 2 data transport protocol.
It is currently widely used in almost all xdsl connections (most DSLAMs operate in ATM), an ATM channel is identified by its VPI/VCI number (VP/VC), usually 8/35 on subscriber-side DSL accesses, then ATM connections go up to the ISP routers: http://perso.orange.fr/wallu/data.htm
browsing speed ...
in principle, it won’t change much for surfing, only the upstream traffic (from your servers to the outside) will be greatly improved.
symmetrical DSL is mainly used for voice connections or to connect servers.
--

and ... Voili Voilou Voila !

8 Mo en Mo est égal à 8 Mo.