Asymptotes of a curve

acacia1952 Posted messages 40 Status Membre -  
 acacia1952 -
Hello my friends

I have two main concerns
1) How to draw an asymptote (vertical, horizontal, and oblique) to a curve in Excel. Example: f(x)=(x^2-4)/(2x+1)?
2) How to chat online on our favorite site howcamarche.net? How to directly ask a question to a friend online and get the answer almost instantly?

9 réponses

Pierr10 Posted messages 13777 Registration date   Status Modérateur Last intervention   5 815
 
Hello everyone

I don’t quite understand what you want to do.

- If it’s about finding the equations of the asymptotes using Excel, I don’t think that’s possible. But since I’m not an Excel specialist, I don’t want to make any assumptions.

- If it’s about plotting the asymptotes, you first need to determine their equations by calculating them by hand and then fill in the table.
I think determining the equations isn’t your problem.
To me, all this is a little bit distant, but if I’m not mistaken, there are:
A “vertical” asymptote with the equation x = -1/2
An oblique asymptote with the equation y = x/2 - 1/4

I made a quick graph with the curve and only the oblique asymptote.
(For the “vertical” asymptote, I’m not sure if that’s possible).
The type of graph to use is “scatter plot” and there are 2 series of points. It looks like this:
I didn’t connect the points, otherwise Excel wouldn’t hesitate to connect the two parts of the curve (just like calculators do, by the way).

As for private messages, yg_be and Raymond Pentier, whom I greet, have already responded. Help in private messaging isn’t in the spirit of the forum because the help we provide to some can serve other members, sometimes much later.
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acacia1952
 
Hello Pierr10
Thank you for your reply.
My problem is as follows:
I am dealing with two functions

1) f(x)=(x-1)/(x+1). I have a vertical asymptote at x=-1 and a horizontal asymptote at y=1 (as x approaches infinity). I would like to be able to plot the branch from ]-infinity ; -1[, then from ]-1 : +infinity[, and finally both asymptotes x = -1 and y = 1

2) f(x)=(2x^2-3)/ (x-1). There is a vertical asymptote at x = 1 and an oblique asymptote y=2x-3 (as x approaches infinity). I would like to be able to plot the branch from ]-infinity ; 1[, then from ]1 : +infinity[

For the vertical asymptotes, I created a column of x with the same value of x (x=-1 for case 1 and x=1 for case 2) and a column of y with different values of y. I plotted the curve, then I copied the two columns and pasted them onto the curve. But there was no result. For the oblique asymptote, I took the values of x from the function's table and the values calculated in y=2x-3. I copied and pasted, but nothing is displayed.
Thank you and have a good Thursday.
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