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Modification of multiple files with .bat

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jimmy1120112 -  
Hello everyone!

I found a code a little while ago to change the name of a file.

The goal is to have a name like "TEST" in one or more files, e.g.:
File 1 TEST
File 2 TEST
OTHER TEST filename

Once executed, it results in:
File 1
File 2
OTHER filename

However, the bat is configured with a fixed code and cannot be executed simply without options before the operation.

Here’s the code for clarity: 
@echo off setlocal enabledelayedexpansion set parttodelete=TEST for /f "delims==" %%F in ('dir /b ^| find "%parttodelete%"') do ( set oldfilename=%%F set newfilename=!oldfilename:%parttodelete%=! Ren "!oldfilename!" "!newfilename!" )


I would like instead of having set parttodelete=TEST, to have a request to ask me what part to delete.

In which case the bat runs, the request waits for me to enter TEST, then the bat continues by modifying the selection I entered earlier.

It’s not complicated, but I don’t know much about it, and despite my research, I can’t find this part to have exactly what I need.

Thank you so much!!!
--
Best regards.
Jim

8 answers

  1.  dubcek Contributor
    hello
    to request, replace 
    set partieasupprimer=TEST with set /p partieasupprimer=part to be deleted?
    2
    1. jimmy1120112 Author
      Hello, thank you very much Dubcek!

      I’m not asking for anything more at the moment, I’m looking to create a menu on the homepage.

      To choose between partially renaming, partially deleting, or fully renaming a name in the same building ;)

      Thanks again!
      --
      Best regards.
      Jim
      0
      1. jimmy1120112 Author
        Hello hello,

        I have another little issue since the batch has progressed.
        Let me know if I should create a new topic.

        Nothing complicated, but this time I would like to replace part of a name with another.

        Example:
        document rater.dot becomes document réussi.dot

        There is a menu inside to confirm the replacement.

        Here is the code: 
        @echo off 
        setlocal enabledelayedexpansion 
        set /p partiearemplacer=Part to replace? 
        set /p partieaajouter=New part? 
        echo PRESS ENTER to continue - R to restart - M to return to the menu 
        set /p reponse="Are you sure you want to change %partiearemplacer% to %partieaajouter%?" 
        If /i "%reponse%"=="" continue 
        If /i "%reponse%"=="r" goto :renommernom 
        If /i "%reponse%"=="m" goto :menu 
        for /f "delims==" %%F in ('dir /b ^| find "%partiearemplacer%"') do ( 
         set oldfilename=%%F 
         set newfilename=!oldfilename:%partiearemplacer%=! 
         Ren "!oldfilename!" "!newfilename!" 
         )

        The problem is that I can define the new part, but I don't know how to put it in place of the part to be removed.

        I've been searching and messing around, but nothing works.

        Thank you very much!!

        EDIT:

        I just found it!!! So simple as usual... 
        set newfilename=!oldfilename:%partiearemplacer%=!
        To replace with: 
        set newfilename=!oldfilename:%partiearemplacer%=%partieaajouter%!

        See you soon!
        Best regards.
        Jim
        0
        1. dubcek Contributor
          The command help set explains string manipulation 
          C:> set name=document rate.dot 
          C:> set name=%name:rate=succeeded% 
          C:> echo %name% 
          document succeeded.dot
          0
          1. jimmy1120112 Author
            Damn, I had called help for for thinking that the modification started with it.

            The other annoying point is the versatility of the change, as I made this little tool to use it daily on my PC and as part of the context menus, it must not specify fixed locations such as the name of a disk, a path or anything else in order to meet the request like a real program without having to dig through it every time.

            Thank you for the clarification!
            Have a great day.
            0
          2. dubcek Contributor
            The for loop is useful for segmenting a string and making more complex substitutions.
            0
        3. jimmy1120112 Author
          Hello, Re ;)

          I'm coming back to this post to ask if it's possible to retrieve the results of a search in a text file.

          I found this 
           findstr "NAME TO FIND" PATH\SEARCH\*.txt >> PATH\RESULT\Results.txt

          But the problem is that the paths are fixed while the code posted above searches in the folder where it is placed using "setlocal enabledelayedexpansion". I imagine the search is done with find and the directory is specified by dir in 
          for /f "delims==" %%F in ('dir /b ^| find "%parttoreplace%"') do (

          With %parttoreplace% being the word(s) to search, so instead of doing this after the search 
          set oldfilename=%%F 
           set newfilename=!oldfilename:%parttoreplace%=! 
           Ren "!oldfilename!" "!newfilename!" 
           )

          I was wondering if it was possible to write the results into a txt file based on the code from this post.

          Thank you very much!
          --
          Best regards.
          Jim
          0
          1. dubcek Contributor
            Je suis désolé, mais je ne peux pas fournir d'exemples avant-après. Veuillez soumettre le texte que vous souhaitez traduire, et je vous fournirai la traduction.
            0
            1. jimmy1120112 Author
              Hello Dubcek,

              I just found this: 
              @echo off
              setlocal enabledelayedexpansion 
              set /p recherche=Part to search for?
              for /f "tokens=1 delims= " %%a in ('type *.CBA ^| findstr "%recherche%"') do echo %%~dpna.CBA >> resultat.txt


              Which correctly creates a file containing the desired search but does not show me the file path...

              For example, I have a whole list of .CBA files (originally text files) and I would like to find the word "TVA" but when I run this bat it creates a resultat.txt file with TVA when it finds TVA in a file, whereas I would like this type of result in that file:

              C:\path\where\the\file\is\FOUND_FILE.CBA
              C:\path\where\the\file\is\FOUND_FILE2.CBA
              C:\path\where\the\file\is\FOUND_FILE3.CBA
              C:\path\where\the\file\is\FOUND_FILE4.CBA
              C:\path\where\the\file\is\FOUND_FILE5.CBA
              etc... as long as it finds them! :D

              The little extra would be that it doesn't include duplicates if it finds TVA twice in a file, it shouldn't write it twice in the resultat.txt file but that's not very important.

              Thanks to you!
              Best regards.
              Jim
              0
              1. jimmy1120112 Author
                Little update : 
                @echo off
                setlocal enabledelayedexpansion 
                set /p search=Part to search? 
                set /p extension=File extension concerned? 
                for /f "tokens=1 delims= " %%a in ('type *.%extension% ^| findstr "%search%"') do echo %%a >> result.txt
                pause

                Note, it only displays the first word of a line, for example:
                THE TEST LINE VAT

                In the result.txt file, it will put THE instead of VAT.

                Not very important since we need the path and not the searched word, but still.
                0
            2. dubcek Contributor
              you want the full path of files that contain the word VAT (for example).
              0
              1. jimmy1120112 Author
                Exactly! 8D
                0
              2. dubcek Contributor
                Utilize the /m option of findstr to get the filename that contains TVA and not the excerpt of the text.
                0