Convert a given IP address to binary using Python
Solved
```python
def ip_vers_ip_binaire(ip):
# Séparer l'adresse IP en octets
octets = ip.split('.')
# Convertir chaque octet en binaire, en supprimant le '0b' et en complétant avec des zéros à gauche
binaire = ''.join(format(int(octet), '08b') for octet in octets)
return binaire
# Exemple d'utilisation
print(ip_vers_ip_binaire('192.168.0.1')) # Sortie : '11000000101010000000000000000001'
```
def ip_vers_ip_binaire(ip):
# Séparer l'adresse IP en octets
octets = ip.split('.')
# Convertir chaque octet en binaire, en supprimant le '0b' et en complétant avec des zéros à gauche
binaire = ''.join(format(int(octet), '08b') for octet in octets)
return binaire
# Exemple d'utilisation
print(ip_vers_ip_binaire('192.168.0.1')) # Sortie : '11000000101010000000000000000001'
```
7 answers
-
Hello,
In my opinion, you should start by splitting the address 192.168 ... into an array of 4 pieces that are each 8 bits
then you write the 4 numbers one after the other without anything in between
So you need the function that splits with a separator which is the dot "." and that gives you the 4 numbers.
Then a print with a binary format in 8 bits.
In my opinion, all of this is in the python documentation.
Take a look :)
https://overapi.com/python
Hints:
there are functions such as:
str.split()
int()
bin()
--
PC seven,
Firefox, Ball mouse... :-b -
yg_be Posted messages 23437 Registration date Status Contributor Last intervention Ambassadeur 1 588
-
Hello,
I'm not looking for the right answer, just some help.
I've already started with this:
def convertir(T): """ T is an array of integers, where the elements are 0 or 1 and represent an integer written in binary. Returns the positive integer whose binary representation is given by the array T """ n = len(T) dec_int = 0 # Initialization of the decimal integer whose binary representation we have for k in range(n): dec_int = dec_int + T[k] * 2 ** (n - 1 - k) return dec_int
Except that if I convert it tostr
, the calculation does not work and I get an error. -
Hello,
can you use code tags when you share code: https://codes-sources.commentcamarche.net/faq/11288-les-balises-de-code
can you show how you call your function?
does your function work well? -
def convert(T) """ T is an array of integers, where the elements are 0 or 1 and represent an integer written in binary. Returns the positive integer whose binary representation is given by the array T """ n = len(T) dec_int = 0 # initialization of the decimal integer whose binary representation we have for k in range(n): dec_int=dec_int+T[k]*2**(n-1-k) return dec_int
-
My function works well but I believe it doesn't help me at all because it converts binary to decimal and I need to do the opposite.
From what I understand, I need to take my data like '192', convert it to binary by adding zeros if necessary, and then "stick" the data together to create a long binary corresponding to each part. -
-
-
Hello,
Regarding message #4, some clarifications.- You indeed need to split your IPv4 address into 4 integers. Each of these integers ranges from 0 to 255 and therefore fits into one byte (that is, 4 integers of 8 bits each, so an IPv4 corresponds to 4 * 8 = 32 bits). For this, you can use the method
split()
.
Example:
(x, y, z, t) = adresse_ip.split(".")- You can convert a string that contains an integer (e.g.,
"192"
) to an integer using the functionint()
.
Example:
i = int("192")- For each of these 4 integers, you can represent it in binary using the function
bin()
. Example:bin(192)
. However, you will see that the returned string is prefixed with"0b"
. If you want to remove this prefix, you just need to consider the binary representation obtained from the second character.
Example:
b = bin(192)[2:]
- By concatenating these four strings, you will obtain the binary representation of your IP address.
Good luck. - You indeed need to split your IPv4 address into 4 integers. Each of these integers ranges from 0 to 255 and therefore fits into one byte (that is, 4 integers of 8 bits each, so an IPv4 corresponds to 4 * 8 = 32 bits). For this, you can use the method
-
So, found it? :)
--
PC seven,
Firefox,
Ball mouse... :-b -
Yes! I've created several functions so that my main function (ip_vers_ip_binaire(ip)) isn't too large
def decimal_en_binaire(a): """a is a positive integer in base 10 Returns its value converted to base 2 as a string """ bin_a = str(a%2) # Initialization of the binary word a = a // 2 while a!=0 : bin_a = str(a % 2) + bin_a a = a//2 return bin_a def ip_vers_liste(ip): """ip is an ipv4 address of type str Returns the array of bytes (in decimal of type int) """ tab_str = ip.split('.') tab_int= [int(k) for k in tab_str] #creation of the array that converts tab_str(type str) to integer (type int) return tab_int def ip_vers_ip_binaire(ip): """ip is an ipv4 address of type str Returns the ip by converting the bytes to binary and without the separating dots. The returned ip is of type str """ ip =ip_vers_liste(ip) #transformation of a string into a list n = len(ip) binn1='' # binn1 is an empty string manque= '0' #manque is used to add 0s to reach 8 bits for each of the 4 parts of the IP binn= '0' for i in range(4): binn= decimal_en_binaire(ip[i]) if len(binn)!=8: binn = manque*(8-len(binn))+ binn binn1= binn1 + binn return binn1 -
I had:
addressIp = "192.168.0.1" # the address we want to process print(addressIp) # just for debugging def ipToBinary(addressIp): toto = addressIp.split('.') result = "" # init result to have string format for counter in toto: #print(counter) # just for debugging result = result+format(int(counter),'08b') print(result) return 0 #launch the action ipToBinary(addressIp)
--
PC seven,
Firefox,
Mouse with ball... :-b -
Hello,
You can make it shorter by using this trick:
def ip_to_binary(ipv4): return "".join( "{0:08b}".format(int(n)) for n in ipv4.split(".") ) print(ip_to_binary("192.168.0.1"))
Good luck-
Bonjour mamie,
can you explain the use of FOR in your example? I don't understand what the part in the join i.e.:"{0:08b}".format(int(n)) for n in ipv4.split(".")
does in front of the for.
For me, the for returns nothing since it's not followed by any instruction.
And the Python 3.10.3 documentation states §8.3 for FOR:
"for_stmt ::= "for" target_list "in" expression_list ":" suite
["else" ":" suite]"
it seems that the ":" is not optional so I don't understand why this doesn't throw an error but let's assume. And we have nothing for suite so there's no action.
If we simplify withn for n in ipv4.split(".")
it works and outputs 19216801, makes sense.
But how? Can you explain or send me to a section of the documentation that will help me understand?
Thank you in advance.- Hello magouero,
What's probably blocking you is that you don't yet know the syntax of thefor
loops used in list comprehensions.
This syntax applies to alist
, atuple
, adict
, a generator.
To be precise, it is more about the syntax associated with a generator that is passed to thelist
,tuple
,dict
constructor.
In the syntax you already know, the function I mentioned can be rewritten as:
def ip_vers_ip_binaire(ipv4): ma_liste = list() for n in ipv4.split("."): ma_liste.append("{0:08b}".format(int(n))) return "".join(ma_liste)
"{0:08b}".format(int(n))means "write the integern
in binary format in at most 8 characters by adding any missing leading 0s to obtain 8 characters". For more details, see this link.
Good luck! - Ok, I see. For the format and the padding, I had it.
But damn, to find that in the documentation without knowing what it's called...
So for those who might read this discussion:
check out
https://docs.python.org/3/tutorial/controlflow.html
then: "generator expression"
https://docs.python.org/3/glossary.html#term-generator
For examples and the interest of the method, the "generator" link above is really good.
Thanks Mamiemando.
-
