Convert a given IP address to binary using Python
Solved
```python
def ip_vers_ip_binaire(ip):
# Séparer l'adresse IP en octets
octets = ip.split('.')
# Convertir chaque octet en binaire, en supprimant le '0b' et en complétant avec des zéros à gauche
binaire = ''.join(format(int(octet), '08b') for octet in octets)
return binaire
# Exemple d'utilisation
print(ip_vers_ip_binaire('192.168.0.1')) # Sortie : '11000000101010000000000000000001'
```
def ip_vers_ip_binaire(ip):
# Séparer l'adresse IP en octets
octets = ip.split('.')
# Convertir chaque octet en binaire, en supprimant le '0b' et en complétant avec des zéros à gauche
binaire = ''.join(format(int(octet), '08b') for octet in octets)
return binaire
# Exemple d'utilisation
print(ip_vers_ip_binaire('192.168.0.1')) # Sortie : '11000000101010000000000000000001'
```
7 réponses
Hello,
In my opinion, you should start by splitting the address 192.168 ... into an array of 4 pieces that are each 8 bits
then you write the 4 numbers one after the other without anything in between
So you need the function that splits with a separator which is the dot "." and that gives you the 4 numbers.
Then a print with a binary format in 8 bits.
In my opinion, all of this is in the python documentation.
Take a look :)
https://overapi.com/python
Hints:
there are functions such as:
str.split()
int()
bin()
--
PC seven,
Firefox, Ball mouse... :-b
In my opinion, you should start by splitting the address 192.168 ... into an array of 4 pieces that are each 8 bits
then you write the 4 numbers one after the other without anything in between
So you need the function that splits with a separator which is the dot "." and that gives you the 4 numbers.
Then a print with a binary format in 8 bits.
In my opinion, all of this is in the python documentation.
Take a look :)
https://overapi.com/python
Hints:
there are functions such as:
str.split()
int()
bin()
--
PC seven,
Firefox, Ball mouse... :-b
yg_be
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Hello,
I'm not looking for the right answer, just some help.
I've already started with this:
Except that if I convert it to
I'm not looking for the right answer, just some help.
I've already started with this:
def convertir(T): """ T is an array of integers, where the elements are 0 or 1 and represent an integer written in binary. Returns the positive integer whose binary representation is given by the array T """ n = len(T) dec_int = 0 # Initialization of the decimal integer whose binary representation we have for k in range(n): dec_int = dec_int + T[k] * 2 ** (n - 1 - k) return dec_int
Except that if I convert it to
str, the calculation does not work and I get an error.
Hello,
can you use code tags when you share code: https://codes-sources.commentcamarche.net/faq/11288-les-balises-de-code
can you show how you call your function?
does your function work well?
can you use code tags when you share code: https://codes-sources.commentcamarche.net/faq/11288-les-balises-de-code
can you show how you call your function?
does your function work well?
def convert(T) """ T is an array of integers, where the elements are 0 or 1 and represent an integer written in binary. Returns the positive integer whose binary representation is given by the array T """ n = len(T) dec_int = 0 # initialization of the decimal integer whose binary representation we have for k in range(n): dec_int=dec_int+T[k]*2**(n-1-k) return dec_int
My function works well but I believe it doesn't help me at all because it converts binary to decimal and I need to do the opposite.
From what I understand, I need to take my data like '192', convert it to binary by adding zeros if necessary, and then "stick" the data together to create a long binary corresponding to each part.
From what I understand, I need to take my data like '192', convert it to binary by adding zeros if necessary, and then "stick" the data together to create a long binary corresponding to each part.
Hello,
Regarding message #4, some clarifications.
Example:
Example:
Example:
Good luck.
Regarding message #4, some clarifications.
- You indeed need to split your IPv4 address into 4 integers. Each of these integers ranges from 0 to 255 and therefore fits into one byte (that is, 4 integers of 8 bits each, so an IPv4 corresponds to 4 * 8 = 32 bits). For this, you can use the method
split()
.
Example:
(x, y, z, t) = adresse_ip.split(".") - You can convert a string that contains an integer (e.g.,
"192"
) to an integer using the functionint()
.
Example:
i = int("192") - For each of these 4 integers, you can represent it in binary using the function
bin()
. Example:bin(192)
. However, you will see that the returned string is prefixed with"0b"
. If you want to remove this prefix, you just need to consider the binary representation obtained from the second character.
Example:
b = bin(192)[2:]
- By concatenating these four strings, you will obtain the binary representation of your IP address.
Good luck.
Yes! I've created several functions so that my main function (ip_vers_ip_binaire(ip)) isn't too large
def decimal_en_binaire(a): """a is a positive integer in base 10 Returns its value converted to base 2 as a string """ bin_a = str(a%2) # Initialization of the binary word a = a // 2 while a!=0 : bin_a = str(a % 2) + bin_a a = a//2 return bin_a def ip_vers_liste(ip): """ip is an ipv4 address of type str Returns the array of bytes (in decimal of type int) """ tab_str = ip.split('.') tab_int= [int(k) for k in tab_str] #creation of the array that converts tab_str(type str) to integer (type int) return tab_int def ip_vers_ip_binaire(ip): """ip is an ipv4 address of type str Returns the ip by converting the bytes to binary and without the separating dots. The returned ip is of type str """ ip =ip_vers_liste(ip) #transformation of a string into a list n = len(ip) binn1='' # binn1 is an empty string manque= '0' #manque is used to add 0s to reach 8 bits for each of the 4 parts of the IP binn= '0' for i in range(4): binn= decimal_en_binaire(ip[i]) if len(binn)!=8: binn = manque*(8-len(binn))+ binn binn1= binn1 + binn return binn1
I had:
--
PC seven,
Firefox,
Mouse with ball... :-b
addressIp = "192.168.0.1" # the address we want to process print(addressIp) # just for debugging def ipToBinary(addressIp): toto = addressIp.split('.') result = "" # init result to have string format for counter in toto: #print(counter) # just for debugging result = result+format(int(counter),'08b') print(result) return 0 #launch the action ipToBinary(addressIp) --
PC seven,
Firefox,
Mouse with ball... :-b
Hello,
You can make it shorter by using this trick:
Good luck
You can make it shorter by using this trick:
def ip_to_binary(ipv4): return "".join( "{0:08b}".format(int(n)) for n in ipv4.split(".") ) print(ip_to_binary("192.168.0.1")) Good luck
Bonjour mamie,
can you explain the use of FOR in your example? I don't understand what the part in the join i.e.:
does in front of the for.
For me, the for returns nothing since it's not followed by any instruction.
And the Python 3.10.3 documentation states §8.3 for FOR:
"for_stmt ::= "for" target_list "in" expression_list ":" suite
["else" ":" suite]"
it seems that the ":" is not optional so I don't understand why this doesn't throw an error but let's assume. And we have nothing for suite so there's no action.
If we simplify with
it works and outputs 19216801, makes sense.
But how? Can you explain or send me to a section of the documentation that will help me understand?
Thank you in advance.
can you explain the use of FOR in your example? I don't understand what the part in the join i.e.:
"{0:08b}".format(int(n)) for n in ipv4.split(".") does in front of the for.
For me, the for returns nothing since it's not followed by any instruction.
And the Python 3.10.3 documentation states §8.3 for FOR:
"for_stmt ::= "for" target_list "in" expression_list ":" suite
["else" ":" suite]"
it seems that the ":" is not optional so I don't understand why this doesn't throw an error but let's assume. And we have nothing for suite so there's no action.
If we simplify with
n for n in ipv4.split(".") it works and outputs 19216801, makes sense.
But how? Can you explain or send me to a section of the documentation that will help me understand?
Thank you in advance.
Hello magouero,
What's probably blocking you is that you don't yet know the syntax of the
This syntax applies to a
To be precise, it is more about the syntax associated with a generator that is passed to the
In the syntax you already know, the function I mentioned can be rewritten as:
Good luck!
What's probably blocking you is that you don't yet know the syntax of the
forloops used in list comprehensions.
This syntax applies to a
list, a
tuple, a
dict, a generator.
To be precise, it is more about the syntax associated with a generator that is passed to the
list,
tuple,
dictconstructor.
In the syntax you already know, the function I mentioned can be rewritten as:
def ip_vers_ip_binaire(ipv4): ma_liste = list() for n in ipv4.split("."): ma_liste.append("{0:08b}".format(int(n))) return "".join(ma_liste) "{0:08b}".format(int(n)) means "write the integer nin binary format in at most 8 characters by adding any missing leading 0s to obtain 8 characters". For more details, see this link.
Good luck!
Ok, I see. For the format and the padding, I had it.
But damn, to find that in the documentation without knowing what it's called...
So for those who might read this discussion:
check out
https://docs.python.org/3/tutorial/controlflow.html
then: "generator expression"
https://docs.python.org/3/glossary.html#term-generator
For examples and the interest of the method, the "generator" link above is really good.
Thanks Mamiemando.
But damn, to find that in the documentation without knowing what it's called...
So for those who might read this discussion:
check out
https://docs.python.org/3/tutorial/controlflow.html
then: "generator expression"
https://docs.python.org/3/glossary.html#term-generator
For examples and the interest of the method, the "generator" link above is really good.
Thanks Mamiemando.
Instead of bin(), there's format(thing, stuff)