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Remove all instances of a single word in Word

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Charly326 -  
 Charly326 -
Hello,

I would like to know how to select all occurrences of the same word in Word (in my case it is "--undefined--") so that I can automatically delete all its occurrences.

I have already tried using the Ctrl + H function (find and replace) but the replacement is done with a space, I would just like it to be deleted without anything else.

I need to be able to select all the "--undefined--" that appear in my document at once.

Thank you very much for your answers.

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Réponse 1 / 1
jee pee Posted messages 31918 Registration date   Status Modérateur Last intervention   9 948
 
Hello,

In the replace function of Word, you can leave by empty, so the word is effectively removed.

Best regards

        a stranger is a friend you haven't met yet.
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Charly326
 
Unfortunately, when I do this, the word is replaced by three empty spaces. I would like it to be simply deleted.
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jee pee Posted messages 31918 Registration date   Status Modérateur Last intervention   9 948 > Charly326
 
it may be that "--undefined--" is preceded and followed by one or more spaces

so these spaces must be taken into account in the "replace", for example replacing " --undefined-- " with nothing
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Charly326
 
Yes indeed, but it always leaves the line. Is a simple selection of all the "--undefined--" not possible?
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jee pee Posted messages 31918 Registration date   Status Modérateur Last intervention   9 948 > Charly326
 
"he always leaves the line break" well yes but you don't say everything at the beginning.

In the replace function, there is a "plus" button for advanced options.

You do your replace --undefined-- plus at the bottom, you select the "special" list and you take either "paragraph break" or "manual line break" or... that adds the concerned special character after --undefined-- and you replace everything with nothing.
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Charly326
 
Ah perfect! Thank you very much!
Sorry, yes, but I'm not very knowledgeable so I had a bit of trouble expressing my problem.
Thank you so much in any case.
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