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Format a number with zeros in Unix shell

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tbeghain Posted messages 63 Status Member -  
 eko -
Hello,

I would like to format a number in Unix shell so that it always has two numeric positions. For example, 1 becomes 01, 2 becomes 02, etc...

Of course, I can do this with a bit of programming, but is it possible to do it with a simple command?

Thank you 
Configuration: AIX 5.2

8 answers

  1.
    jipicy Posted messages 40842 Registration date   Status Moderator Last intervention   4 898
     
    Hello,
    [tmpfs]$ for i in $(seq 10); do printf "%02d\n" "$i"; done 01 02 03 04 05 06 07 08 09 10
    ;-))

    --
    Z'@+...che.
    JP : Zen, my Nuggets ! ;-) Knowledge is only good when it is shared.
    2
    1. lami20j Posted messages 21506 Registration date   Status Moderator, Security Contributor Last intervention   3 571
       
      That's no longer synchronization
      It's at a higher level, telepathy for example ;-))
      --
      lami20j
      0
      1. jipicy Posted messages 40842 Registration date   Status Moderator Last intervention   4 898 > lami20j Posted messages 21506 Registration date   Status Moderator, Security Contributor Last intervention  
         
        It's clear ;-))

        But there must have been some interference, I didn't quite catch the "20" ;-DDDDD

        --
        Z'@+...che.
        JP : Zen, my Nuggets ! ;-) Knowledge is only valuable if it's shared.
        0
  2. lami20j Posted messages 21506 Registration date   Status Moderator, Security Contributor Last intervention   3 571
     
    Hello,

    there is the printf command 
    root@debian:~# for i in $(seq 20);do printf "%02d\n" $i;done 01 02 03 04 05 06 07 08 09 10 11 12 13 14 15 16 17 18 19 20

    --
    lami20j
    1
  3. Gotrune Posted messages 55 Registration date   Status Member 3
     

    '0'&$1
    0
  4. tbeghain Posted messages 63 Status Member 3
     
    Thank you very much, the printf does exactly what I wanted.
    0
  6. tbeghain Posted messages 63 Status Member 3
     
    Sorry, but I have a weird little thing with printf specifically with the numbers 8 and 9 exclusively

    When running the following script:
    AA=` printf "%02d\n" "07" `
    echo $AA
    AA=` printf "%02d\n" "08" `
    echo $AA
    AA=` printf "%02d\n" "09" `
    echo $AA
    AA=` printf "%02d\n" "10" `
    echo $AA
    AA=` printf "%02d\n" "7" `
    echo $AA
    AA=` printf "%02d\n" "8" `
    echo $AA
    AA=` printf "%02d\n" "9" `
    echo $AA

    I get the following results

    07
    printf: 08 not completely converted
    00
    printf: 09 not completely converted
    00
    10
    07
    08
    09

    Why do 08 and 09 not work???? while all other numbers pass???? Is it due to my Unix? Who has cursed the 8 and 9?
    0
  7. jipicy Posted messages 40842 Registration date   Status Moderator Last intervention   4 898
     
    I assure you that under GNU/Linux I have exactly the same problem and I don't know why!?

    I have tried all forms of "quotation" in all kinds (i>single, double, with, without, etc.) and nothing works!!!

    Even without using a variable, in pure command line, it crashes ;-((

    Any solutions, leads or hints of explanation will be welcome.

    Thank you.

    --
    Z'@+...che.
    JP : Zen, my Nuggets ! ;-) Knowledge is only good when it is shared.
    0
  8. lami20j Posted messages 21506 Registration date   Status Moderator, Security Contributor Last intervention   3 571
     
    Hello,

    try this
    lami20j@debian:~$ cat ccm.sh #!/bin/bash AA=` printf "%02.f\n" "07" ` echo $AA AA=` printf "%02.f\n" "08" ` echo $AA AA=` printf "%02.f\n" "09" ` echo $AA AA=` printf "%02.f\n" "10" ` echo $AA AA=` printf "%02.f\n" "7" ` echo $AA AA=` printf "%02.f\n" "8" ` echo $AA AA=` printf "%02.f\n" "9" ` echo $AA lami20j@debian:~$ sh ccm.sh 07 08 09 10 07 08 09


    --
    lami20j
    0
    1. jipicy Posted messages 40842 Registration date   Status Moderator Last intervention   4 898
       
      You math nerd ;-))

      Thank you.

      --
      Z'@+...che.
      JP : Zen, my Nuggets ! ;-) Knowledge is only good if it is shared.
      0
  9. lami20j Posted messages 21506 Registration date   Status Moderator, Security Contributor Last intervention   3 571
     
    When you write 01, 02 ... 08, 09 the numbers are interpreted as octal
    in octal 8 = 10 and 9 = 11

    An octal number cannot contain digits beyond 7 inclusive 
     lami20j@debian:~$ printf "%o and %o and %o\n" 0777 777 521 777 and 1411 and 1011 lami20j@debian:~$

    however when you write 8 and 9 these are decimal numbers so I can convert them to octal 
    lami20j@debian:~$ printf "%o and %o\n" 8 9 10 and 11

    --
    lami20j
    0
    1. jipicy Posted messages 40842 Registration date   Status Moderator Last intervention   4 898
       
      Thank you very much lami20j ;-))

      --
      Z'@+...che.
      JP : Zen, my Nuggets ! ;-) Knowledge is only good if it is shared.
      0
      1. lami20j Posted messages 21506 Registration date   Status Moderator, Security Contributor Last intervention   3 571 > jipicy Posted messages 40842 Registration date   Status Moderator Last intervention  
         
        You're welcome :-))
        --
        lami20j
        0
      2. eko > lami20j Posted messages 21506 Registration date   Status Moderator, Security Contributor Last intervention  
         
        I would need help; I have the same problem, except that I would like to do it with numbers in base 16.
        Thank you in advance.
        0