Replace a color in an object

Magueul Posted messages 10 Status Membre -  
contrariness Posted messages 338 Registration date   Status Membre Last intervention   -
Hello,

I would like to know if anyone knows a way to replace one color with another,
but not the method "Select -> Same" because it doesn't work for what I want to do...

In my object, I have lots of shapes, and some have Fill: Black / Stroke: White and others Stroke: Black / Fill: White.
If I want to replace ONLY the black, whether it's a fill or a stroke, is there an automatic way to do it?

Thanks a lot!

1 réponse

contrariness Posted messages 338 Registration date   Status Membre Last intervention   6 240
 
It seems to me that this is only possible if the color you want to modify is a "direct tone"...

With a CMYK (or other) black or RGB, it is not possible except with the similar object selection function.
0
Magueul Posted messages 10 Status Membre
 
Oh really? I didn't think it could change anything..
Thanks anyway for the answer!
0
contrariness Posted messages 338 Registration date   Status Membre Last intervention   6 240
 
A direct tone is a color that has a name and is printed independently of others (in separation). This is the principle for Pantone colors, which are pure shades.

In this case, it is possible to replace one name with another and associate a color with it, and everything that bears the same name changes color...
0
Magueul Posted messages 10 Status Membre
 
I don't think there are any options even for direct tones... I think what I'm looking for doesn't exist.
0
contrariness Posted messages 338 Registration date   Status Membre Last intervention   6 240
 
It's even simpler than I thought... because it also works with CMYK shades or others... but on the condition that it's a shade from the swatch (and not a shade given in CMYK via the "color" palette)...

It's in the swatch that you can change the color... and automatically all the objects that have that color are modified at the same time.

Therefore, you need to create a color in the swatch for that.
0