code source java

Question

Bonjour, 

je suis débutante en programmation java ,j'ai trouver  un code pour ouvrir un fichier texte mais j'ai besoin de lire seulement des lignes de ce  fichier comment faire ça?
mon code source est:

package todo;

import java.io.BufferedReader;
import java.io.FileNotFoundException;
import java.io.FileReader;
import java.io.IOException;
import java.util.Scanner;

public class openfile {
    public static void main(String[] args){
        Scanner scanner = new Scanner(System.in);
        BufferedReader br = null;
        String line;
        
        System.out.println("Please enter the file name to be read");
        
        try{
            br = new BufferedReader(new FileReader("C:\Users\Khaoula\Desktop\file to read\" + scanner.next()));
            
        } catch (FileNotFoundException fnfex) {
            System.out.println(fnfex.getMessage() +"the file was not found");
            System.exit(0);
            
        }
        
        try {
            while((line = br.readLine()) !=null)
                System.out.println(line);
        } catch (IOException ioex) {
            System.out.println(ioex.getMessage() + "Error reading file");
        } finally{
            System.exit(0);

}
    
}
}
Configuration: Windows 7 / Chrome 48.0.2564.116

KX · Answer

Bonjour,

Plus simple :

import java.io.IOException;
import java.nio.file.Files;
import java.nio.file.Paths;

public class Test{
    public static void main(String[] args) throws IOException {
        for (String line : Files.readAllLines(Paths.get("C:/test.txt")))
            System.out.println(line);
    }
}

Code source java

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