[JAVA]Request to enter a variable Solved

Question

Hello everyone.
I recently finished the beginner part of my book on programming that talked about Java. It’s all nice, I’m thinking, I know the basics of Java. While waiting to buy a more complex and specialized book, I’m going to make some cool little programs. I start a class, I open the braces, I declare a few variables and then I wonder... how do you ask the user to enter a variable (Input in BASIC)??? I re-open my book... Nothing about that... :-O
So I would like to know how to ask the user to enter an integer, decimal, or string (String) variable. A simple example will be enough for me.

Thank you in advance.

Lila · Accepted Answer

The simplest way to ask the user to enter something is to use Scanner.

So, you import it:

import java.util.Scanner;

then, you use it:

Scanner userInput = new Scanner(System.in);

Now, you need to know what you want the user to enter as a value (int, float, double, string, char,...) depending on the type:

System.out.println("Please enter a word:");
String str = userInput.next();

System.out.println("Please enter an integer:");
int ent = userInput.nextInt();

... Etc,...

Canard007 · Answer

import java.io.*; public static void main(String[] args) { do { task.showHello(); System.out.println("Do you want to continue?
"); try { BufferedReader br = new BufferedReader(new InputStreamReader(System.in)); String response = br.readLine(); System.out.println(response); if(response.equals("y")) { test=0; } } catch(IOException e) { System.out.println(e.toString()); } }while(test==1); }  Well, there are plenty of other methods, especially if you're doing graphical interfaces, but here it’s the low level as they say ^^ COIN!

silfaxu · Answer

Hello,

Try this:

try {
BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
String str = "";
while (str != null) {
System.out.print("> prompt ");
str = in.readLine();
}
} catch (IOException e) {
}

In str, you have your text ..

@+

sfx

marco · Answer

Hi, after several readings on OOP, the beginning of practice is difficult for me, I have never programmed in my life, I wanted to learn practically the rules of syntactical coordination in OOP.

Onde2Choc · Answer

Oh, is it that complicated? I imagined a simple operator like in Basic... Alright, Java is not Basic ;-) Thank you for your answers!

9amar · Answer

```html
How to enter a variable by a user in Java
```

dahu2004 · Answer

Hello,
I tried this method, but I'm encountering a problem. When I try to compare my string with an if statement, for example:

if(src == "yes")
return 1;

the condition is always false. However, when I ask it to display my variable, it correctly shows "yes". Is it due to the buffer?
Thank you in advance.

Oh, by the way, I don't know if it influences anything, I don't think so, but I modified the text ">prompt".

dahu2004 · Answer

It's all good, thank you very much!

dahu2004 · Answer

In fact, the problem was that I was comparing my strings with == instead of .equals.

[JAVA]Request to enter a variable

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