10 milliards
Solved
Krystal
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Duck -
Duck -
Hello,
I would like to know the result (and the calculation method!) to determine the number of possible combinations for 10-digit numbers (0 1 2 3 4 5 6 7 8 9) knowing that the numbers start with 1, 2, 3, 4, or 5.
The digits can be used multiple times in the same number!
I was told about 1.8 million possibilities, but that seems low to me!
Thanks to whoever can help me!
Configuration: Windows 7 / Firefox 26.0
I would like to know the result (and the calculation method!) to determine the number of possible combinations for 10-digit numbers (0 1 2 3 4 5 6 7 8 9) knowing that the numbers start with 1, 2, 3, 4, or 5.
The digits can be used multiple times in the same number!
I was told about 1.8 million possibilities, but that seems low to me!
Thanks to whoever can help me!
Configuration: Windows 7 / Firefox 26.0
1 réponse
Hello
You can have 5,000,000,000 possibilities
Explanations:
for numbers starting with 1: you can have from 1,000,000,000 to 1,999,999,999, which is 1,000,000,000 possibilities
for numbers starting with 2: you can have from 2,000,000,000 to 2,999,999,999, which is 1,000,000,000 possibilities
...
So that's 5 x 1,000,000,000 = 5,000,000,000
--
he who holds knowledge holds power
You can have 5,000,000,000 possibilities
Explanations:
for numbers starting with 1: you can have from 1,000,000,000 to 1,999,999,999, which is 1,000,000,000 possibilities
for numbers starting with 2: you can have from 2,000,000,000 to 2,999,999,999, which is 1,000,000,000 possibilities
...
So that's 5 x 1,000,000,000 = 5,000,000,000
--
he who holds knowledge holds power
I would rather say 6,000,000,000 possibilities. From 0 to 5,999,999,999.
Zero is not a digit, it's an addition; it creates a digit but it is not one because you can buy something with one euro, but with 0 € you can't buy anything.