pb de code php dans javascript Fermé

Question

bonjour, j'ai un pb lorsque j'insère un code php dans le code javascript par exemple:

rasta67 · Accepted Answer

bonjour,

pas possible de faire du php dans javascript

php executé sur le serveur
javascript chez le client

sp4tz · Answer

Salut,, écrit ton code javascripte dans un echo php: var obj = new AW.UI.Grid; obj.setCellData([ for($i=0;$i<4;$i++){ echo'['; for($j=0;$j<4;$j++){ print \"\"\"; echo $tab[$i][$j]; print \"\"\"; if($j!=3) echo','; } echo ']'; if($j!=3) echo','; } ]); "; ?>

wolfgyone · Answer

Si tu as vraiment besoin d exécuter du php dans du javascript recherche l'objet XHR

regardes ici

function showResultsTableRight()
{
    //alert("xhr_url = "+xhr_url);
    //alert("enter showResultsTableRight");
    // 1. catch dynamic data from server thanks to Ajax    
    // 1.1 clear area before displaying result(s)
    document.getElementById("resultsTableDiv").innerHTML = null;

    // 1.2 collect data to do correct operation in db
    var act = 'getrightlist';
    var dataArray = collectSearchFormDataRight();
    var data = "act="+act+"&label="+dataArray[0];

    // 1.3 use xmlhttprequest object
    var xhr_object = GetXmlHttpRequest();

    // 1.4 open 'facade' file to access data (via an object)
    xhr_object.open("POST", "/efstc/dev/php/facade/Facade_right.php", true);
	
    // 1.5 server is ready
    xhr_object.onreadystatechange = function()
    {
        /*if(xhr_object.readyState == 4 && xhr_object.status == 200)
        {
            //alert(xhr_object.responseText);
            document.getElementById("resultsTableDiv").innerHTML = xhr_object.responseText;
        }*/

        // waiting until request is achieved
        if((xhr_object.readyState == 1) ||(xhr_object.readyState == 2) || (xhr_object.readyState == 3))
            document.getElementById("resultsTableDiv").innerHTML = 'LOADING...';
        // now we can read server response
        else if(xhr_object.readyState == 4)
        {
            if(xhr_object.status == 200)    // continue only if HTTP status is 'OK'
                document.getElementById("resultsTableDiv").innerHTML = xhr_object.responseText;
            else    // display error message
                alert('in js_user.js file
There was a problem retrieving the data:
'+xhr_object.statusText);
        }
    }

    xhr_object.setRequestHeader("Content-type", "application/x-www-form-urlencoded");   // mandatory if method = POST

    // 2. send data to server
    xhr_object.send(data);   // in case of method = POST

    // 3. display div which is in charge of results table
    document.getElementById("resultsTableDiv").style.visibility = "visible";
}

Pb de code php dans javascript

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