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Opening an Excel file from VBA code

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TraderAS -  
Hello,

I want to open an Excel file using the following code:

Sub Ouvrir()
Workbooks.Open Filename:="C:\Documents and Settings\Administrateur\Bureau\TRADING\Action.xlsx"
End Sub

However, when I run it, I get this error
==> Incorrect statement outside of a procedure, and it highlights this part in blue:
C:\Documents and Settings\Administrateur\Bureau\TRADING\Action.xlsx

Thank you.

2 answers

  1.  pijaku Moderator
    Hello,

    In VBA Excel, try this: 
    Sub Open() Dim Path As String, FileName As String Path = "C:\Documents and Settings\Administrator\Desktop\TRADING\" FileName = "Action.xlsx" Workbooks.Open Filename:= Path & FileName End Sub

    Sources
    --
    Best regards,
    Franck P
    10