Affichage de listes en fonction de boutons

Bonjour,

bonjour, j'ai 2 boutons radio et 2 listes, comment afficher chaque liste en fonction de chaque bouton radio, voici mon code mais je ne sais pas comment continuer:

<td><input type="radio" name="formation" value="0" id="radiobutton" />
<label for="radiobutton"><span class="gras1">Formation diplomante</span>
<input type="radio" name="formation" value="1" id="radio" />
<span class="gras1">Formation spécialisée</span></label></td>
</tr>
<tr valign="baseline">
<td align="right" nowrap class="gras1">Formation diplomante::</td>

<td><label for="select"></label>
<select name="select" id="select">
<?php

echo '<option value="-1">--liste specialite--</option>'."\n";
$result = mysql_query("SELECT * FROM specialite where id_form= 1 " );
while($data = mysql_fetch_array($result))
{
echo '<option value="'.$data['id_spec'].'">'.$data['nom_spec'];
echo '</option>'."\n";
}
echo '</select>'."\n";
?>


</select>
</td>
</tr>
<tr valign="baseline">
<td align="right" nowrap class="gras1">Formation spécialisée::</td>
<td><label for="label"></label>
<select name="select2" id="label">
<?php echo '<option value="-1">--liste specialite--</option>'."\n";
$result = mysql_query("SELECT * FROM specialite where id_form= 2 " );
while($data = mysql_fetch_array($result))
{
echo '<option value="'.$data['id_spec'].'">'.$data['nom_spec'];
echo '</option>'."\n";
}

echo '</select>'."\n";




?>rokaya

Messages: 1
Inscrit le: Mar 22 Nov 2011 14:32