[python] application d'une formule de proba

function factorielle($valeur){
	$fact = 1;
	for($i = 1; $i <= $valeur; $i++)
		$fact *= $i;
	return $fact;
}

function combinaison($k, $n){
	return (factorielle($n) / (factorielle($k) * factorielle($n - $k)));
}

function maFonction($a, $b, $c){
	$resu = 0;
	for($k = $c + 1; $k <= $b; $k++){
		$temp = combinaison($k, $b);
		$temp *= pow((1/$a), $k);
		$temp *= pow((1 - 1/$a), $b - $k);
		
		$resu += $temp;
		
	}
	$resu = $resu * 100;
	$resu = 100 - $resu;
	return round($resu,3);
}

def survival(request):
	a = request.GET.get('a','')
	b = request.GET.get('b','')
	c = request.GET.get('c','')
	
	
	def facto(valeur):
		x = 1
		fact = 1
		while x < valeur:
			fact = fact * x
			x = x + 1
		return fact

	def combinaison(k, n):
		return facto(n) / ( facto(k) * facto(n - k) )

	def mafonction(a, b, c):
		if a != '' and b != '' and c != '':
			a = int(a)
			b = int(b)
			c = int(c)
			resu = 0
			k = c + 1
			while k <= b:
				temp = combinaison(k, b)
				temp = temp * ((1 / a)**k)
				temp = temp * (1 - 1/a)**( b - k)
				resu = resu + temp
				k = k + 1
			resu = resu * 100
			resu = 100 - resu
			return round(resu, 3)
		else:
			return False

	def mafonction2(a, b, c):
		if a != '' and b != '' and c != '':
			a = int(a)
			b = int(b)
			c = int(c)
			resu = 0
			k = c + 1
			while k <= b:
				temp = combinaison(k, b)
				temp = temp * ((1 / a)**k)
				temp = temp * (1 - 1/a)** ( b - k)
				resu = resu + temp
				k = k + 1
			resu = resu * 100
			resu = 100 - resu
			return combinaison(k, b)
		else:
			return False

	now = datetime.datetime.now()
	t = get_template('test.php')
	html = t.render(Context({
	'total': mafonction(a, b, c),
	}))
	return HttpResponse(html)