Keyboard input (java)

I think you understood why: the locale...

Dan

You're too strong :)

It works, thank you very much
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The truth belongs to those who seek it, not to those who claim to possess it.
(don't forget to mark resolved if you have found your happiness: think of others^^')

make a test by entering 0.2 >>>> comma

Dan

It shows

Exception :
java.util.InputMismatchException
at java.util.Scanner.throwFor(Unknown Source)
at java.util.Scanner.next(Unknown Source)
at java.util.Scanner.nextDouble(Unknown Source)
at TestLissage.main(TestLissage.java:44)

so it corresponds to this line:

h = s.nextDouble();
--
The truth belongs to those who seek it and not to those who claim to possess it.
(don't forget to mark resolved if you have found your happiness: think of others^^')

Re,

To get the StackTrace list, you add this to each catch:

 catch(Exception e) { System.err.println("Exception :"); e.printStackTrace(); } 

Dan

Sorry, she's there, I'm looking!!!

I only provided the relevant part and made sure it compiles:

 import java.io.IOException; import java.util.Scanner; class TestLissage { public static int n; public static double y0, x0, Yn, Xn, h; public static int choix; public static void main(String[] args) { while (choix != 6 && choix != 5 && choix != 4 && choix != 3 && choix != 2 && choix != 1 && choix != 7) { System.out.println("please choose the application to solve:"); System.out.println(""); System.out.println("1: y'(x) = x + y(x) solution: y(x) = exp(x)-x-1 with y(0) = 0"); System.out.println("2: y'(x) = -2xy(x) solution: y(x) = exp(-x²) with y(0) = 1"); System.out.println("3: y'(x) = -xy²(x) solution: y(x) = 2/(1+x²) with y(0) = 2"); System.out.println("4: y'(x) = y(x) solution: y(x) = exp(x) with y(0) = 1"); System.out.println("5: y'(x) = "); System.out.println("6: y'(x) = "); System.out.println("7: exit"); try { Scanner s = new Scanner(System.in); System.out.println("enter your choice"); choix = s.nextInt(); } catch(Exception e){} } if (choix == 1 || choix == 2 || choix == 3 || choix == 4 || choix == 5 || choix == 6) { try { Scanner s = new Scanner(System.in); System.out.println("enter the number of iterations"); n = s.nextInt(); } catch(Exception e){} try { Scanner s = new Scanner(System.in); System.out.println("enter the iteration step"); h = s.nextDouble(); } catch(Exception e){} System.out.println(choix); System.out.println(n); System.out.println(h); } } 

--
Truth belongs to those who seek it and not to those who claim to possess it.
(don't forget to mark it solved if you have found your happiness: think of others^^')

Hello,

Please provide us with the part of the code concerned, it will be easier to correct...

Best regards,

Dan

I'm having trouble putting it in :s I don't know how to do it, it's not working IOException e
--
The truth belongs to those who seek it and not to those who claim to hold it.
(don't forget to mark resolved if you found your happiness: think of others^^')

The try block doesn't work, the program compiles, everything works except for this part, h = s.nextDouble();

It directly goes into the catch and doesn't display h :( because the try didn't work.

Basically, how do we record a keyboard input of type 0.x?

--
The truth belongs to those who seek it, not to those who claim to possess it.
(don't forget to mark as resolved if you found your happiness: think of others^^')

Hello,

what is not "working"? compilation error or runtime error? is it doing something it shouldn't? is it not doing something it should? if so, what? "With 0.2 for example": does that mean it doesn't work with 0.2, but it works with something else? if so, what? if not, it should be specified.

Otherwise, I see something strange: System.out.println("no h :(");

This will not display the value of h....