run a .py file

Question

Hello,  I downloaded a script from the internet, so I opened it with Python since it is in .py format, and I would like to run the program. What should I do?

sebsauvage · Accepted Answer

Open an MS-Dos window,  type: python monprogramme.py   If it doesn't work, you need to add Python to the PATH (environment variable).

sebsauvage · Answer

to run a Python program, 2 solutions:  - In a command window, type: python programme.py - Rename the .py to .pyw and double-click on it (but in this case, you won't see the console)

Mouchasounet · Answer

Yes, but it doesn't execute (nothing launches in .pyw).

sebsauvage · Answer

It’s that the program displays things in the console. So it needs to be run in a console (and not as .pyw).

Mouchasounet · Answer

And how?

Mouchasounet · Answer

"Python : Impossible d'ouvrir le fichier "statliars.py""

sebsauvage · Answer

Did you navigate to the directory of your .py program before typing the command?

Mouchasounet · Answer

No, how should I do it?

sebsauvage · Answer

Use the CD command to change the directory and place yourself in the directory where your script is located.

Mouchasounet · Answer

Here I start and he tells me "Usage statsliar.py python url "

Mouchasounet · Answer

Here’s what it looks like:  http://img72.imageshack.us/img72/8287/pythonmn9.jpg

Mouchasounet · Answer

Maybe an error in the code..

#!/usr/bin/env python # devloop 2006 import sys, socket, urllib2 if len(sys.argv) < 2: print "Usage: python statsliar.py url <referer_url>" sys.exit(1) url = sys.argv[1] if not url.startswith("http://"): print "Not a valid url" sys.exit(1) if len(sys.argv) == 3: if sys.argv[2].startswith("http://"): referer = sys.argv[2] else: print "Not a valid referer" sys.exit(1) else: referer = "" head = {'User-agent': 'Mozilla/4.0 (compatible; MSIE 5.5; Windows NT)', 'Referer': 'http://proxy-list.org/downloadproxylist.php?sp=-1&pp=any&pt=any&pc=any&ps=any'} socket.setdefaulttimeout(10) try: req = urllib2.Request("http://proxy-list.org/downloadproxylist.php?sp=-1&pp=any&pt=any&pc=any&ps=any", headers=head) proxylist = urllib2.urlopen(req).readlines() except IOError: print "Error reading proxy list" sys.exit(1) print "Fetching url " + url head = {'User-agent': 'Mozilla/4.0 (compatible; MSIE 5.5; Windows NT)'} if referer != "": head["Referer"] = referer print "Using referer " + referer for prox in proxylist: prox = prox.strip() try: req = urllib2.Request(url, headers=head) req.set_proxy(prox, 'http') urllib2.urlopen(req) except IOError: continue print prox</referer_url>

sebsauvage · Answer

Here I get started and he tells me "Usage statsliar.py python url <referer_url>  Here he indicates how to use the software. It means that you need to pass a URL in the command line.  Example: python statsliar.py https://www.toto.com/   If I understand correctly, this script is used to manipulate the stats of a site using proxies.  Hmmpf... :-/ What I think about it, huh...

Mouchasounet · Answer

Yes, but why do they give me an error after?

sebsauvage · Answer

No idea.  At my place, the line socket.setdefaulttimeout(10) does not cause any error.  What version of Python do you have? Type: python --version

Mouchasounet · Answer

I have Python 2.2.3

sebsauvage · Answer

That must be why.  Uninstall your version of Python and install 2.5.1: https://www.python.org/ftp/python/2.5.1/python-2.5.1.msi

Mouchasounet · Answer

Here's how to add Python to the PATH.

sebsauvage · Answer

Right-click on My Computer > Properties
Advanced tab
"Environment Variables" button

In the lower part (System variables)
select PATH and click on the "Edit" button.

In "Variable value", go to the end of the line and add:

;c:\python25

(Don't forget the semicolon just before c:\python25)

Confirm everything by clicking OK.

You may need to restart for the changes to take effect.

kumakuma215 · Answer

Hello, CMD does not recognize the Python command, what should I do???

Run a .py file

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