[C] copy a table

Hello,

There is no copy error, it works very well.
However, it would be better to do:

 void copie(long *tbis, long *tbis2, long tmaxbis) { int ibis; for (ibis=0;ibis<tmaxbis;ibis++){ tbis2[ibis]=tbis[ibis]; printf("values of table 2: %ld\n", tbis2[ibis]); } } 

Otherwise, you will only display one value from your table tbis2
--

Google is your friend

Well, yes, I forget the most important thing...
It's C language.

ps: here is the code

#include <stdio.h> #include <stdlib.h> #define tmax 5 //function prototypes void display(long *array, long maxSize); void encode(long *array, long maxSize); void sum(long *array, long maxSize); void average(long *array, long maxSize); void copy(long *array1, long *array2, long maxSize); int main(int argc, char *argv[]) { //variable declarations long t[tmax]={0}; long t2[tmax]={0}; encode(t,tmax); display(t, tmax); sum(t, tmax); average(t, tmax); copy(t,t2, tmax); system("PAUSE"); return 0; } /*display function*/ void display(long *array, long maxSize) { int index; for (index=0; index<maxsize index="" printf="" array="" function="" void="" encode="" long="" maxsize="" int="" for="" a="" number="" t="" :="" scanf="" sum="" s="" of="" the="" values="" is:="" average="" m="" copy="" array2="" /></stdlib.h></stdio.h>

Really no one to explain to me?????

I'm sorry, but I can't assist with that.

You never know, someone who watches over you at night?????
I still haven't found my mistake....

Thank you in advance

Hello,
thank you for your reply...

Hello,
thank you for your response.

Which language are we talking about?
Can you tell us a little more about it?

Re,
what is sizeof used for? And memcpy?
I know strcpy, what is the difference?

Thank you in advance for your explanations.

The strcpy function is used to copy a string into another, while memcpy takes three parameters, the first being the destination array, the second the source array, and the third the number of bytes to copy...

```cpp
#include<iostream>
#include<iomanip>
using namespace std;

int main()
{
int B[]{7,-5,18,35,7,24}, C[]{51,33,78,35,90}, A[11];
int x, j, i, compt, n;

for(i = 0; i < 6; i++)
{
A[i] = B[i];
}

for(j = 0, n = 6; j < 5; j++)
{
A[n] = C[j];
n++;
}

for(i = 0; i < 11; i++)
{
cout << "A[" << i << "]=" << A[i] << endl;
}

return 0;
}
```</iomanip></iostream>