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8-digit combination

Jeanne -  
Pierr10 Posted messages 13775 Registration date   Status Modérateur Last intervention   -

Hello,

I would like to have the complete list of all possible combinations of an 8-digit number, using the digits 0, 1, 2, 3, 4, 5, 6, 7, 8, 9. Considering that a digit can be repeated several times.
Is it possible, or are there really too many of them??

Thank you for your help ????????????

3 réponses

Réponse 1 / 3
georges97 Posted messages 14506 Registration date   Status Contributeur Last intervention   2 895
 

Hello, The question has already been asked on CCM, and answers were proposed, see: https://forums.commentcamarche.net/forum/affich-21869547-combinaison-de-8-chiffres#2

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Réponse 2 / 3
baladur13 Posted messages 47547 Registration date   Status Modérateur Last intervention   14 372
 

The right answer is here:
https://forums.commentcamarche.net/forum/affich-21869547-combinaison-de-8-chiffres#p21874447
See also https://www.dcode.fr/combinaisons-avec-repetition
https://img-19.ccm2.net/n1vaXfZxLkA2kxy-n55zyH3AMcY=/3ba2970d3dc7496f99cf6d97f8c89ec1/ccm-ugc/capture.png

Very difficult to catch a black cat in a dark room.
Especially when it’s not there...
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Réponse 3 / 3
Pierr10 Posted messages 13775 Registration date   Status Modérateur Last intervention   5 808
 

Hello,

Since the numbers can be repeated, the problem is trivial. There are 10^8 (that is, 100,000,000) possible combinations, meaning all the numbers between 00 000 000 and 99 999 999.

What one clearly conceives can be clearly stated,
And the words to express it come easily.
(Boileau)
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