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8-digit combination

Jeanne -  
Pierr10 Posted messages 13854 Registration date   Status Moderator Last intervention   -

Hello,

I would like to have the complete list of all possible combinations of an 8-digit number, using the digits 0, 1, 2, 3, 4, 5, 6, 7, 8, 9. Considering that a digit can be repeated several times.
Is it possible, or are there really too many of them??

Thank you for your help ????????????

3 answers

  1.
    georges97 Posted messages 14627 Registration date   Status Contributor Last intervention   2 944
     

    Hello, The question has already been asked on CCM, and answers were proposed, see: https://forums.commentcamarche.net/forum/affich-21869547-combinaison-de-8-chiffres#2

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  2. baladur13 Posted messages 47388 Registration date   Status Moderator Last intervention   14 405
     

    The right answer is here:
    https://forums.commentcamarche.net/forum/affich-21869547-combinaison-de-8-chiffres#p21874447
    See also https://www.dcode.fr/combinaisons-avec-repetition
    https://img-19.ccm2.net/n1vaXfZxLkA2kxy-n55zyH3AMcY=/3ba2970d3dc7496f99cf6d97f8c89ec1/ccm-ugc/capture.png

    Very difficult to catch a black cat in a dark room.
    Especially when it’s not there...
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  3. Pierr10 Posted messages 13854 Registration date   Status Moderator Last intervention   5 854
     

    Hello,

    Since the numbers can be repeated, the problem is trivial. There are 10^8 (that is, 100,000,000) possible combinations, meaning all the numbers between 00 000 000 and 99 999 999.

    What one clearly conceives can be clearly stated,
    And the words to express it come easily.
    (Boileau)
    0