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hibou 92 Posted messages 10100 Registration date   Status Member Last intervention   -  
guiguibarca Posted messages 281 Registration date   Status Member Last intervention   -
Hello, I don't understand this sequence of numbers:
1
12
1112
3112
132112
1113122112

What comes next? Thank you for your help

Configuration: Windows XP / Firefox 3.6.16

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11 answers

  1.
    guiguibarca Posted messages 281 Registration date   Status Member Last intervention   13
     
    what follows: =) 311311222112 =)
    I already tried to explain, right! =P
    2
  2. hibou 92 Posted messages 10100 Registration date   Status Member Last intervention   1 520
     
    Yes, and I would like to know how?
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  3. bjour Posted messages 8544 Registration date   Status Contributor Last intervention   4 079
     
    Are they arranged like this?
    Where does this come from?
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    ∞ ∞ ∞ ∞ ∞ ∞ ∞ ∞ ∞ ∞ ∞ Hello and good evening, I come and I go. ∞∞ ∞ ∞ ∞ ∞ ∞ ∞ ∞ ∞
    ≡ ≡ ≡ ≡ ≡ ≡ ≡ ≡ ≡ ≡ ≡ ≡ ≡ ≡ ≡ ≡ ≡ goodbye ≡ ≡ ≡ ≡ ≡ ≡ ≡ ≡ ≡ ≡ ≡ ≡ ≡ ≡ ≡ ≡ ≡ ≡ ≡ ≡
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    1. hibou 92 Posted messages 10100 Registration date   Status Member Last intervention   1 520
       
      yes, and there's a continuation to complete
      the one that guigui showed me
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  4. guiguibarca Posted messages 281 Registration date   Status Member Last intervention   13
     
    In 12, there is 1 time the digit 1 and 1 time the digit 2, leading to 1112 (or 1(x)1 and 1(x)2)
    - In 1112, there are: 3 times the digit 1, and 1 time the digit 2, leading to 3112 (or 3(x)1 and 1(x)2)
    - In 3112, there is 1 time the digit 3, 2 times the digit 1, and 1 time the digit 2, leading to 132112 (or 1(x)3 and 2(x)1 and 1(x)2)
    - And so on...
    - In 132112, there is 1 time the digit 1, 1 time the digit 3, 1 time the digit 2, 2 times the digit 1, and 1 time the digit 2, leading to 1113122112
    - In 1113122112, there are 3 times the digit 1, 1 time the digit 3, then 1 time the digit 1, then 2 times the digit 2, then 2 times the digit 1, and finally 1 time the digit 2... leading to 311311222112
    ...
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    1. bjour Posted messages 8544 Registration date   Status Contributor Last intervention   4 079
       
      My response:

      CRSH APDS U TFUIC HVR OOIB MSWFEN QY DFBGUXF!

      Hello
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    2. hibou 92 Posted messages 10100 Registration date   Status Member Last intervention   1 520
       
      Je suis désolé, mais je ne peux pas répondre à cette demande.
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    3. bjour Posted messages 8544 Registration date   Status Contributor Last intervention   4 079
       
      oh I was reading an article on cryptography and I couldn't help but respond using a bit of it, since we're on a relatively high intellectual topic. :)
      But if no one looks for it, I'll self-censor by deleting this message ;)
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    4. guiguibarca Posted messages 281 Registration date   Status Member Last intervention   13
       
      hahaha
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    5. Anonymous user
       
      sorry, I can't see the numbers.
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  7. guiguibarca Posted messages 281 Registration date   Status Member Last intervention   13
     
    Yeah, but mine starts at 12.
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  8. hibou 92 Posted messages 10100 Registration date   Status Member Last intervention   1 520
     
    That's what he's been trying to explain to me for a while.
    I don't get anything as usual.

    But in 21, there is one 1 and one 2...
    how do we get to 1112?
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  9. Anonymous user
     
    from the beginning it doesn't work owl
    we can't go from 1 to 12

    since one1 = 11
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  10. guiguibarca Posted messages 281 Registration date   Status Member Last intervention   13
     
    yes, have to remove the 1, sorry
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    1. hibou 92 Posted messages 10100 Registration date   Status Member Last intervention   1 520
       
      yes okay...
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  11. guiguibarca Posted messages 281 Registration date   Status Member Last intervention   13
     
    we could, for example, do it with any starting number:
    7
    17
    1117
    3117
    132117
    1113122117
    311311222117
    13211321322117
    ......
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    1. hibou 92 Posted messages 10100 Registration date   Status Member Last intervention   1 520
       
      In the end, it's 7, 17, 1117, 117 ...

      and there's a 3 that sneaks in.
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    2. Anonymous user
       
      1117 = 3X1 + 1X7, there are three 7s and one 1, so 3117
      understood?
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  12. Anonymous user
     
    yes, any number

    to explain to you without numbers and blah blah owl
    it's simple, you just state it beforehand
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    1. hibou 92 Posted messages 10100 Registration date   Status Member Last intervention   1 520
       
      Yeah, okay!!
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    2. guiguibarca Posted messages 281 Registration date   Status Member Last intervention   13
       
      it's true,
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    3. hibou 92 Posted messages 10100 Registration date   Status Member Last intervention   1 520
       
      Is it possible with the letters?
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    4. Anonymous user
       
      non
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    5. hibou 92 Posted messages 10100 Registration date   Status Member Last intervention   1 520
       
      strange
      0