View original (French)

ASCII sorting

Solved
Sabetodo -  
Hello,
Hi, I'm trying to sort the command line arguments in ASCII order on Unix (Ubuntu) but I'm having trouble. Please, help me guys.
Here's my code: 
int main( int argc, char **argv) { int i,j; char* temp; for(i=0; i<argc -1 ; i++) { for(j = i+1 ; j<argc; j++) { if(argv[ i ] > argv[ j ]) { temp = argv[ i ]; argv[i] = argv[ j ]; argv[j] = temp; } } } for(i=0; i<argc; i++) { my_putstr(argv[i]); my_putstr("\n"); } return(0); }


Example:
$>./a.out test "This is a test" retest | cat -e
./a.out$
This is a test $
retest$
test$
$>
Configuration: Linux Firefox 1.0.7

4 answers

  1. toto
    Hello

    There is (at least) one problem with your comparison: 
    argv[ i ] > argv[ j ]

    argv[i] and argv[j] are pointers, you are comparing the values of the pointers and not the pointed strings
    To compare the pointed strings, you need to use the strcmp() function (I'm quoting from memory, check the details in your C manual)
    0